3n^2+13n-870=0

Solution for 3n^2+13n-870=0 equation:

3n^2+13n-870=0

a = 3; b = 13; c = -870;
Δ = b2-4ac
Δ = 132-4·3·(-870)
Δ = 10609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10609}=103$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-103}{2*3}=\frac{-116}{6}
=-19+1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+103}{2*3}=\frac{90}{6}
=15
$